1/x-2+1/x+3=1/x^2+-6

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Solution for 1/x-2+1/x+3=1/x^2+-6 equation: 



1/x-2+1/x+3=1/x^2+-6

We move all terms to the left:

1/x-2+1/x+3-(1/x^2+-6)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2+-6)!=0

x∈R



We add all the numbers together, and all the variables

1/x+1/x-(1/x^2+-6)+1=0

We use the square of the difference formula

1/x+1/x-(1/x^2-6)+1=0

We get rid of parentheses

1/x+1/x-1/x^2+6+1=0

We calculate fractions

We do not support expression: x^3

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